Base | Representation |
---|---|
bin | 110000011011100100111011… |
… | …100111110011000101000111 |
3 | 1000221011201121202112011201102 |
4 | 300123210323213303011013 |
5 | 210404303142212232421 |
6 | 2033003241424450315 |
7 | 62602560052644146 |
oct | 6033447347630507 |
9 | 1027151552464642 |
10 | 213001313399111 |
11 | 61961393532256 |
12 | 1ba810b8a7999b |
13 | 91b0c26094023 |
14 | 3a8546625775d |
15 | 19959bdbb160b |
hex | c1b93b9f3147 |
213001313399111 has 2 divisors, whose sum is σ = 213001313399112. Its totient is φ = 213001313399110.
The previous prime is 213001313399101. The next prime is 213001313399233. The reversal of 213001313399111 is 111993313100312.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213001313399111 - 210 = 213001313398087 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213001313399101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106500656699555 + 106500656699556.
It is an arithmetic number, because the mean of its divisors is an integer number (106500656699556).
Almost surely, 2213001313399111 is an apocalyptic number.
213001313399111 is a deficient number, since it is larger than the sum of its proper divisors (1).
213001313399111 is an equidigital number, since it uses as much as digits as its factorization.
213001313399111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13122, while the sum is 38.
Adding to 213001313399111 its reverse (111993313100312), we get a palindrome (324994626499423).
The spelling of 213001313399111 in words is "two hundred thirteen trillion, one billion, three hundred thirteen million, three hundred ninety-nine thousand, one hundred eleven".
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