Base | Representation |
---|---|
bin | 1100011001011111101… |
… | …0100110111110011111 |
3 | 202100210111001212120212 |
4 | 3012113322212332133 |
5 | 11442212020333434 |
6 | 241503554403035 |
7 | 21250251104444 |
oct | 3062772467637 |
9 | 670714055525 |
10 | 213002121119 |
11 | 82374165247 |
12 | 35345b9047b |
13 | 17116c84478 |
14 | a448c3d9cb |
15 | 5819b948ce |
hex | 3197ea6f9f |
213002121119 has 4 divisors (see below), whose sum is σ = 214178928600. Its totient is φ = 211825313640.
The previous prime is 213002121091. The next prime is 213002121127. The reversal of 213002121119 is 911121200312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 213002121119 - 236 = 144282644383 is a prime.
It is a super-2 number, since 2×2130021211192 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 213002121094 and 213002121103.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (213002121139) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 588403469 + ... + 588403830.
It is an arithmetic number, because the mean of its divisors is an integer number (53544732150).
Almost surely, 2213002121119 is an apocalyptic number.
213002121119 is a deficient number, since it is larger than the sum of its proper divisors (1176807481).
213002121119 is a wasteful number, since it uses less digits than its factorization.
213002121119 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1176807480.
The product of its (nonzero) digits is 216, while the sum is 23.
The spelling of 213002121119 in words is "two hundred thirteen billion, two million, one hundred twenty-one thousand, one hundred nineteen".
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