Base | Representation |
---|---|
bin | 11110111111110101001… |
… | …000000001001001101000 |
3 | 21112122012211002100211220 |
4 | 132333311020001021220 |
5 | 234344442030100204 |
6 | 4310321512422040 |
7 | 306616251400011 |
oct | 36776510011150 |
9 | 7478184070756 |
10 | 2130121331304 |
11 | 751419a60a1a |
12 | 2a49b93a7920 |
13 | 125b3c60aa75 |
14 | 75154100008 |
15 | 3a62180b1d9 |
hex | 1eff5201268 |
2130121331304 has 64 divisors (see below), whose sum is σ = 5757084724800. Its totient is φ = 654489621504.
The previous prime is 2130121331263. The next prime is 2130121331309. The reversal of 2130121331304 is 4031331210312.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is not an unprimeable number, because it can be changed into a prime (2130121331309) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63109057 + ... + 63142800.
It is an arithmetic number, because the mean of its divisors is an integer number (89954448825).
Almost surely, 22130121331304 is an apocalyptic number.
2130121331304 is a gapful number since it is divisible by the number (24) formed by its first and last digit.
It is an amenable number.
2130121331304 is an abundant number, since it is smaller than the sum of its proper divisors (3626963393496).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
2130121331304 is a wasteful number, since it uses less digits than its factorization.
2130121331304 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 126251922 (or 126251918 counting only the distinct ones).
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 2130121331304 its reverse (4031331210312), we get a palindrome (6161452541616).
The spelling of 2130121331304 in words is "two trillion, one hundred thirty billion, one hundred twenty-one million, three hundred thirty-one thousand, three hundred four".
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