213020000113 has 4 divisors (see below), whose sum is σ = 217973953648. Its totient is φ = 208066046580.

The previous prime is 213020000111. The next prime is 213020000191. The reversal of 213020000113 is 311000020312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213020000113 - 2¹ = 213020000111 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213020000093 and 213020000102.

It is not an unprimeable number, because it can be changed into a prime (213020000111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2476976703 + ... + 2476976788.

It is an arithmetic number, because the mean of its divisors is an integer number (54493488412).

Almost surely, 2^213020000113 is an apocalyptic number.

It is an amenable number.

213020000113 is a deficient number, since it is larger than the sum of its proper divisors (4953953535).

213020000113 is an equidigital number, since it uses as much as digits as its factorization.

213020000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4953953534.

The product of its (nonzero) digits is 36, while the sum is 13.

Adding to 213020000113 its reverse (311000020312), we get a palindrome (524020020425).

The spelling of 213020000113 in words is "two hundred thirteen billion, twenty million, one hundred thirteen", and thus it is an aban number.