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2130314302115 = 5426062860423
BaseRepresentation
bin11111000000000000101…
…000001001001010100011
321112122201021012022000222
4133000000220021022203
5234400340430131430
64310353004433255
7306624113540066
oct37000050111243
97478637168028
102130314302115
1175150898282a
122a4a51b4882b
13125b705a378c
14751719b28dd
153a6337279e5
hex1f000a092a3

2130314302115 has 4 divisors (see below), whose sum is σ = 2556377162544. Its totient is φ = 1704251441688.

The previous prime is 2130314302093. The next prime is 2130314302117. The reversal of 2130314302115 is 5112034130312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 2130314302115 - 220 = 2130313253539 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2130314302117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213031430207 + ... + 213031430216.

It is an arithmetic number, because the mean of its divisors is an integer number (639094290636).

Almost surely, 22130314302115 is an apocalyptic number.

2130314302115 is a deficient number, since it is larger than the sum of its proper divisors (426062860429).

2130314302115 is an equidigital number, since it uses as much as digits as its factorization.

2130314302115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 426062860428.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 2130314302115 its reverse (5112034130312), we get a palindrome (7242348432427).

The spelling of 2130314302115 in words is "two trillion, one hundred thirty billion, three hundred fourteen million, three hundred two thousand, one hundred fifteen".

Divisors: 1 5 426062860423 2130314302115