Base | Representation |
---|---|
bin | 10011110101110001… |
… | …101001000000001111 |
3 | 2000222122220202220020 |
4 | 103311301221000033 |
5 | 322112121100421 |
6 | 13441523353223 |
7 | 1352626030452 |
oct | 236561510017 |
9 | 60878822806 |
10 | 21303300111 |
11 | 9042180755 |
12 | 4166522813 |
13 | 20166c9a32 |
14 | 1061425499 |
15 | 84a3addc6 |
hex | 4f5c6900f |
21303300111 has 4 divisors (see below), whose sum is σ = 28404400152. Its totient is φ = 14202200072.
The previous prime is 21303300091. The next prime is 21303300121. The reversal of 21303300111 is 11100330312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21303300111 - 29 = 21303299599 is a prime.
It is a super-2 number, since 2×213033001112 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21303300121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3550550016 + ... + 3550550021.
It is an arithmetic number, because the mean of its divisors is an integer number (7101100038).
Almost surely, 221303300111 is an apocalyptic number.
21303300111 is a deficient number, since it is larger than the sum of its proper divisors (7101100041).
21303300111 is an equidigital number, since it uses as much as digits as its factorization.
21303300111 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 7101100040.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 21303300111 its reverse (11100330312), we get a palindrome (32403630423).
The spelling of 21303300111 in words is "twenty-one billion, three hundred three million, three hundred thousand, one hundred eleven".
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