Base | Representation |
---|---|
bin | 1100011001101001100… |
… | …0000101110101011111 |
3 | 202100220100202021020011 |
4 | 3012122120011311133 |
5 | 11442303102413002 |
6 | 241512031304051 |
7 | 21251262025201 |
oct | 3063230056537 |
9 | 670810667204 |
10 | 213043404127 |
11 | 823954a1834 |
12 | 3535797b027 |
13 | 171226a9c98 |
14 | a450508771 |
15 | 581d5eb8d7 |
hex | 319a605d5f |
213043404127 has 2 divisors, whose sum is σ = 213043404128. Its totient is φ = 213043404126.
The previous prime is 213043404097. The next prime is 213043404137. The reversal of 213043404127 is 721404340312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213043404127 - 223 = 213035015519 is a prime.
It is a super-3 number, since 3×2130434041273 (a number of 35 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213043404137) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106521702063 + 106521702064.
It is an arithmetic number, because the mean of its divisors is an integer number (106521702064).
Almost surely, 2213043404127 is an apocalyptic number.
213043404127 is a deficient number, since it is larger than the sum of its proper divisors (1).
213043404127 is an equidigital number, since it uses as much as digits as its factorization.
213043404127 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 16128, while the sum is 31.
Adding to 213043404127 its reverse (721404340312), we get a palindrome (934447744439).
The spelling of 213043404127 in words is "two hundred thirteen billion, forty-three million, four hundred four thousand, one hundred twenty-seven".
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