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2131031101207 is a prime number
BaseRepresentation
bin11111000000101011010…
…110100000111100010111
321112201120012222110112111
4133000223112200330113
5234403322430214312
64310552052131451
7306650636326261
oct37005326407427
97481505873474
102131031101207
11751846556578
122a5012006b87
13125c55c45358
14751dcc80b31
153a6766178a7
hex1f02b5a0f17

2131031101207 has 2 divisors, whose sum is σ = 2131031101208. Its totient is φ = 2131031101206.

The previous prime is 2131031101193. The next prime is 2131031101229. The reversal of 2131031101207 is 7021011301312.

It is an a-pointer prime, because the next prime (2131031101229) can be obtained adding 2131031101207 to its sum of digits (22).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2131031101207 - 235 = 2096671362839 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2131031101607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065515550603 + 1065515550604.

It is an arithmetic number, because the mean of its divisors is an integer number (1065515550604).

Almost surely, 22131031101207 is an apocalyptic number.

2131031101207 is a deficient number, since it is larger than the sum of its proper divisors (1).

2131031101207 is an equidigital number, since it uses as much as digits as its factorization.

2131031101207 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 252, while the sum is 22.

Adding to 2131031101207 its reverse (7021011301312), we get a palindrome (9152042402519).

The spelling of 2131031101207 in words is "two trillion, one hundred thirty-one billion, thirty-one million, one hundred one thousand, two hundred seven".