213103130213333 has 4 divisors (see below), whose sum is σ = 213415140653568. Its totient is φ = 212791119773100.

The previous prime is 213103130213329. The next prime is 213103130213381. The reversal of 213103130213333 is 333312031301312.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 213103130213333 - 2² = 213103130213329 is a prime.

It is a super-2 number, since 2×213103130213333² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213103130213296 and 213103130213305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213103130213933) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 156005219093 + ... + 156005220458.

It is an arithmetic number, because the mean of its divisors is an integer number (53353785163392).

Almost surely, 2^{213103130213333} is an apocalyptic number.

It is an amenable number.

213103130213333 is a deficient number, since it is larger than the sum of its proper divisors (312010440235).

213103130213333 is an equidigital number, since it uses as much as digits as its factorization.

213103130213333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 312010440234.

The product of its (nonzero) digits is 8748, while the sum is 29.

Adding to 213103130213333 its reverse (333312031301312), we get a palindrome (546415161514645).

The spelling of 213103130213333 in words is "two hundred thirteen trillion, one hundred three billion, one hundred thirty million, two hundred thirteen thousand, three hundred thirty-three".