Base | Representation |
---|---|
bin | 1100011001110111101… |
… | …1111011100110001111 |
3 | 202101001112010201010102 |
4 | 3012131323323212033 |
5 | 11442413400143043 |
6 | 241522003401315 |
7 | 21252615504116 |
oct | 3063573734617 |
9 | 671045121112 |
10 | 213103131023 |
11 | 82416186502 |
12 | 3537398323b |
13 | 17131b8c843 |
14 | a458414c7d |
15 | 58239986b8 |
hex | 319defb98f |
213103131023 has 2 divisors, whose sum is σ = 213103131024. Its totient is φ = 213103131022.
The previous prime is 213103130987. The next prime is 213103131053. The reversal of 213103131023 is 320131301312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 213103131023 - 214 = 213103114639 is a prime.
It is a super-3 number, since 3×2131031310233 (a number of 35 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 213103130986 and 213103131004.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213103131053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106551565511 + 106551565512.
It is an arithmetic number, because the mean of its divisors is an integer number (106551565512).
Almost surely, 2213103131023 is an apocalyptic number.
213103131023 is a deficient number, since it is larger than the sum of its proper divisors (1).
213103131023 is an equidigital number, since it uses as much as digits as its factorization.
213103131023 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 213103131023 its reverse (320131301312), we get a palindrome (533234432335).
The spelling of 213103131023 in words is "two hundred thirteen billion, one hundred three million, one hundred thirty-one thousand, twenty-three".
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