Base | Representation |
---|---|
bin | 10011110110001100… |
… | …110100011111001011 |
3 | 2001000011022202110022 |
4 | 103312030310133023 |
5 | 322120432100120 |
6 | 13442340211055 |
7 | 1353043424024 |
oct | 236614643713 |
9 | 61004282408 |
10 | 21310425035 |
11 | 90461a7819 |
12 | 4168999a8b |
13 | 2018022a73 |
14 | 106235bc4b |
15 | 84ad1a025 |
hex | 4f63347cb |
21310425035 has 4 divisors (see below), whose sum is σ = 25572510048. Its totient is φ = 17048340024.
The previous prime is 21310425029. The next prime is 21310425041. The reversal of 21310425035 is 53052401312.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (21310425029) and next prime (21310425041).
It is a cyclic number.
It is not a de Polignac number, because 21310425035 - 210 = 21310424011 is a prime.
It is a super-3 number, since 3×213104250353 (a number of 32 digits) contains 333 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21310424995 and 21310425013.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2131042499 + ... + 2131042508.
It is an arithmetic number, because the mean of its divisors is an integer number (6393127512).
Almost surely, 221310425035 is an apocalyptic number.
21310425035 is a deficient number, since it is larger than the sum of its proper divisors (4262085013).
21310425035 is an equidigital number, since it uses as much as digits as its factorization.
21310425035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4262085012.
The product of its (nonzero) digits is 3600, while the sum is 26.
Adding to 21310425035 its reverse (53052401312), we get a palindrome (74362826347).
The spelling of 21310425035 in words is "twenty-one billion, three hundred ten million, four hundred twenty-five thousand, thirty-five".
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