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2131110231132 = 223177592519261
BaseRepresentation
bin11111000000110000000…
…100010111110001011100
321112201202201212200101110
4133000300010113301130
5234404003204344012
64311004000142020
7306652620036621
oct37006004276134
97481681780343
102131110231132
11751887193003
122a5034607910
13125c6945c6ac
147520959c348
153a67d54873c
hex1f030117c5c

2131110231132 has 12 divisors (see below), whose sum is σ = 4972590539336. Its totient is φ = 710370077040.

The previous prime is 2131110231119. The next prime is 2131110231181. The reversal of 2131110231132 is 2311320111312.

It is a tau number, because it is divible by the number of its divisors (12).

It is a junction number, because it is equal to n+sod(n) for n = 2131110231099 and 2131110231108.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 88796259619 + ... + 88796259642.

Almost surely, 22131110231132 is an apocalyptic number.

It is an amenable number.

2131110231132 is an abundant number, since it is smaller than the sum of its proper divisors (2841480308204).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

2131110231132 is a wasteful number, since it uses less digits than its factorization.

2131110231132 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 177592519268 (or 177592519266 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 2131110231132 its reverse (2311320111312), we get a palindrome (4442430342444).

The spelling of 2131110231132 in words is "two trillion, one hundred thirty-one billion, one hundred ten million, two hundred thirty-one thousand, one hundred thirty-two".

Divisors: 1 2 3 4 6 12 177592519261 355185038522 532777557783 710370077044 1065555115566 2131110231132