Base | Representation |
---|---|
bin | 110000011101001011010001… |
… | …011100001110101001111010 |
3 | 1000221120020021000200100101010 |
4 | 300131023101130032221322 |
5 | 210413103214442144010 |
6 | 2033125533444134350 |
7 | 62613530142155541 |
oct | 6035132134165172 |
9 | 1027506230610333 |
10 | 213111201131130 |
11 | 619a3a53271805 |
12 | 1ba9a4660973b6 |
13 | 91bb3b9243473 |
14 | 3a8a8cc575158 |
15 | 19987a0ece620 |
hex | c1d2d170ea7a |
213111201131130 has 128 divisors (see below), whose sum is σ = 554613495448320. Its totient is φ = 52286793431040.
The previous prime is 213111201131099. The next prime is 213111201131201. The reversal of 213111201131130 is 31131102111312.
213111201131130 is digitally balanced in base 2 and base 4, because in such bases it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 213111201131097 and 213111201131106.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 67937377 + ... + 71004996.
It is an arithmetic number, because the mean of its divisors is an integer number (4332917933190).
Almost surely, 2213111201131130 is an apocalyptic number.
213111201131130 is an abundant number, since it is smaller than the sum of its proper divisors (341502294317190).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213111201131130 is a wasteful number, since it uses less digits than its factorization.
213111201131130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 138942496.
The product of its (nonzero) digits is 108, while the sum is 21.
Adding to 213111201131130 its reverse (31131102111312), we get a palindrome (244242303242442).
The spelling of 213111201131130 in words is "two hundred thirteen trillion, one hundred eleven billion, two hundred one million, one hundred thirty-one thousand, one hundred thirty".
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