Base | Representation |
---|---|
bin | 110000011101001011011000… |
… | …100111000100101100101000 |
3 | 1000221120020120102000101001112 |
4 | 300131023120213010230220 |
5 | 210413103441240230230 |
6 | 2033125553422205452 |
7 | 62613533132440001 |
oct | 6035133047045450 |
9 | 1027506512011045 |
10 | 213111321414440 |
11 | 619a40051573a9 |
12 | 1ba9a49a423888 |
13 | 91bb408139317 |
14 | 3a8a9005261a8 |
15 | 19987ab83dd95 |
hex | c1d2d89c4b28 |
213111321414440 has 128 divisors (see below), whose sum is σ = 492902823628800. Its totient is φ = 82894937099520.
The previous prime is 213111321414391. The next prime is 213111321414469. The reversal of 213111321414440 is 44414123111312.
It is a junction number, because it is equal to n+sod(n) for n = 213111321414397 and 213111321414406.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 220964699 + ... + 221927061.
It is an arithmetic number, because the mean of its divisors is an integer number (3850803309600).
Almost surely, 2213111321414440 is an apocalyptic number.
213111321414440 is a gapful number since it is divisible by the number (20) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 213111321414440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (246451411814400).
213111321414440 is an abundant number, since it is smaller than the sum of its proper divisors (279791502214360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
213111321414440 is a wasteful number, since it uses less digits than its factorization.
213111321414440 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 963447 (or 963443 counting only the distinct ones).
The product of its (nonzero) digits is 9216, while the sum is 32.
Adding to 213111321414440 its reverse (44414123111312), we get a palindrome (257525444525752).
The spelling of 213111321414440 in words is "two hundred thirteen trillion, one hundred eleven billion, three hundred twenty-one million, four hundred fourteen thousand, four hundred forty".
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