Base | Representation |
---|---|
bin | 110000011101001011011000… |
… | …101001010110011100011110 |
3 | 1000221120020120110010200221222 |
4 | 300131023120221112130132 |
5 | 210413103441413331142 |
6 | 2033125553443053342 |
7 | 62613533140504322 |
oct | 6035133051263436 |
9 | 1027506513120858 |
10 | 213111322011422 |
11 | 619a400552497a |
12 | 1ba9a49a671252 |
13 | 91bb4082b7c73 |
14 | 3a8a90063d982 |
15 | 19987ab90abd2 |
hex | c1d2d8a5671e |
213111322011422 has 32 divisors (see below), whose sum is σ = 333576221587200. Its totient is φ = 101996217792000.
The previous prime is 213111322011383. The next prime is 213111322011443. The reversal of 213111322011422 is 224110223111312.
213111322011422 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 213111322011391 and 213111322011400.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10546097 + ... + 23182812.
It is an arithmetic number, because the mean of its divisors is an integer number (10424256924600).
Almost surely, 2213111322011422 is an apocalyptic number.
213111322011422 is a deficient number, since it is larger than the sum of its proper divisors (120464899575778).
213111322011422 is a wasteful number, since it uses less digits than its factorization.
213111322011422 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 33730052.
The product of its (nonzero) digits is 1152, while the sum is 26.
Adding to 213111322011422 its reverse (224110223111312), we get a palindrome (437221545122734).
The spelling of 213111322011422 in words is "two hundred thirteen trillion, one hundred eleven billion, three hundred twenty-two million, eleven thousand, four hundred twenty-two".
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