Base | Representation |
---|---|
bin | 110000011101001100000111… |
… | …101000000110110000111111 |
3 | 1000221120022121101021112220201 |
4 | 300131030013220012300333 |
5 | 210413112100203323312 |
6 | 2033130204001024331 |
7 | 62613561521224531 |
oct | 6035140750066077 |
9 | 1027508541245821 |
10 | 213112110214207 |
11 | 619a437a438336 |
12 | 1ba9a67a6250a7 |
13 | 91bb50269a249 |
14 | 3a8a9771b7851 |
15 | 1998805c02557 |
hex | c1d307a06c3f |
213112110214207 has 2 divisors, whose sum is σ = 213112110214208. Its totient is φ = 213112110214206.
The previous prime is 213112110214183. The next prime is 213112110214243. The reversal of 213112110214207 is 702412011211312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213112110214207 - 231 = 213109962730559 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213112110214907) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106556055107103 + 106556055107104.
It is an arithmetic number, because the mean of its divisors is an integer number (106556055107104).
Almost surely, 2213112110214207 is an apocalyptic number.
213112110214207 is a deficient number, since it is larger than the sum of its proper divisors (1).
213112110214207 is an equidigital number, since it uses as much as digits as its factorization.
213112110214207 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 28.
Adding to 213112110214207 its reverse (702412011211312), we get a palindrome (915524121425519).
The spelling of 213112110214207 in words is "two hundred thirteen trillion, one hundred twelve billion, one hundred ten million, two hundred fourteen thousand, two hundred seven".
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