Base | Representation |
---|---|
bin | 11111000000110001010… |
… | …000111110011000011111 |
3 | 21112201211010122220110120 |
4 | 133000301100332120133 |
5 | 234404023324442343 |
6 | 4311005554410023 |
7 | 306653252524233 |
oct | 37006120763037 |
9 | 7481733586416 |
10 | 2131130312223 |
11 | 751897559250 |
12 | 2a503b290913 |
13 | 125c706709b3 |
14 | 7520c1085c3 |
15 | 3a6801b3683 |
hex | 1f03143e61f |
2131130312223 has 64 divisors (see below), whose sum is σ = 3271707210240. Its totient is φ = 1222421657600.
The previous prime is 2131130312219. The next prime is 2131130312231. The reversal of 2131130312223 is 3222130311312.
It is not a de Polignac number, because 2131130312223 - 22 = 2131130312219 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2131130312193 and 2131130312202.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2131130312243) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6215140 + ... + 6549062.
It is an arithmetic number, because the mean of its divisors is an integer number (51120425160).
Almost surely, 22131130312223 is an apocalyptic number.
2131130312223 is a deficient number, since it is larger than the sum of its proper divisors (1140576898017).
2131130312223 is a wasteful number, since it uses less digits than its factorization.
2131130312223 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 334120.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 2131130312223 its reverse (3222130311312), we get a palindrome (5353260623535).
The spelling of 2131130312223 in words is "two trillion, one hundred thirty-one billion, one hundred thirty million, three hundred twelve thousand, two hundred twenty-three".
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