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21312032201431 is a prime number
BaseRepresentation
bin1001101100010000110000…
…00110111101101011010111
32210110102002011112010021221
410312020120012331223113
510243134020220421211
6113154340141351211
74326513011514616
oct466103006755327
983412064463257
1021312032201431
116877422635254
1224824b8568507
13bb794010899a
1453971780787d
1526e59528cc71
hex1362181bdad7

21312032201431 has 2 divisors, whose sum is σ = 21312032201432. Its totient is φ = 21312032201430.

The previous prime is 21312032201407. The next prime is 21312032201497. The reversal of 21312032201431 is 13410223021312.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21312032201431 - 223 = 21312023812823 is a prime.

It is a super-2 number, since 2×213120322014312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 21312032201396 and 21312032201405.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21312032201401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656016100715 + 10656016100716.

It is an arithmetic number, because the mean of its divisors is an integer number (10656016100716).

Almost surely, 221312032201431 is an apocalyptic number.

21312032201431 is a deficient number, since it is larger than the sum of its proper divisors (1).

21312032201431 is an equidigital number, since it uses as much as digits as its factorization.

21312032201431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 21312032201431 its reverse (13410223021312), we get a palindrome (34722255222743).

The spelling of 21312032201431 in words is "twenty-one trillion, three hundred twelve billion, thirty-two million, two hundred one thousand, four hundred thirty-one".