Base | Representation |
---|---|
bin | 11111000000110110000… |
… | …001011011000001011111 |
3 | 21112202000200211121221201 |
4 | 133000312001123001133 |
5 | 234404204242340221 |
6 | 4311021525140331 |
7 | 306655242063625 |
oct | 37006601330137 |
9 | 7482020747851 |
10 | 2131210121311 |
11 | 751928609a77 |
12 | 2a5061b5a6a7 |
13 | 125c840651cb |
14 | 75218961515 |
15 | 3a6871ca891 |
hex | 1f03605b05f |
2131210121311 has 8 divisors (see below), whose sum is σ = 2181668114384. Its totient is φ = 2080792808640.
The previous prime is 2131210121309. The next prime is 2131210121323. The reversal of 2131210121311 is 1131210121312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 2131210121311 - 21 = 2131210121309 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2131210122311) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 10064070 + ... + 10273651.
It is an arithmetic number, because the mean of its divisors is an integer number (272708514298).
Almost surely, 22131210121311 is an apocalyptic number.
2131210121311 is a deficient number, since it is larger than the sum of its proper divisors (50457993073).
2131210121311 is a wasteful number, since it uses less digits than its factorization.
2131210121311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 20340201.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 2131210121311 its reverse (1131210121312), we get a palindrome (3262420242623).
Subtracting from 2131210121311 its reverse (1131210121312), we obtain a palindrome (999999999999).
The spelling of 2131210121311 in words is "two trillion, one hundred thirty-one billion, two hundred ten million, one hundred twenty-one thousand, three hundred eleven".
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