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21312115010149 is a prime number
BaseRepresentation
bin1001101100010000111010…
…00010110110101001100101
32210110102021221100020111111
410312020131002312221211
510243134202420311044
6113154352300305021
74326515035416505
oct466103502665145
983412257306444
1021312115010149
116877465354707
122482520242171
13bb7954310622
14539724801a05
1526e59c698b34
hex13621d0b6a65

21312115010149 has 2 divisors, whose sum is σ = 21312115010150. Its totient is φ = 21312115010148.

The previous prime is 21312115010089. The next prime is 21312115010201. The reversal of 21312115010149 is 94101051121312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 19626610017249 + 1685504992900 = 4430193^2 + 1298270^2 .

It is a cyclic number.

It is not a de Polignac number, because 21312115010149 - 211 = 21312115008101 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21312115010149.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21312115010449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656057505074 + 10656057505075.

It is an arithmetic number, because the mean of its divisors is an integer number (10656057505075).

Almost surely, 221312115010149 is an apocalyptic number.

It is an amenable number.

21312115010149 is a deficient number, since it is larger than the sum of its proper divisors (1).

21312115010149 is an equidigital number, since it uses as much as digits as its factorization.

21312115010149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 31.

The spelling of 21312115010149 in words is "twenty-one trillion, three hundred twelve billion, one hundred fifteen million, ten thousand, one hundred forty-nine".