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2131212013432 = 23475668117057
BaseRepresentation
bin11111000000110110001…
…000101000111101111000
321112202000211101202110021
4133000312020220331320
5234404210233412212
64311022033500224
7306655264134205
oct37006610507570
97482024352407
102131212013432
11751929691607
122a5062711674
13125c845784c8
1475218cd4cac
153a687451307
hex1f036228f78

2131212013432 has 16 divisors (see below), whose sum is σ = 4081044281760. Its totient is φ = 1042933538304.

The previous prime is 2131212013429. The next prime is 2131212013433. The reversal of 2131212013432 is 2343102121312.

It is a junction number, because it is equal to n+sod(n) for n = 2131212013397 and 2131212013406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (2131212013433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2834058153 + ... + 2834058904.

It is an arithmetic number, because the mean of its divisors is an integer number (255065267610).

Almost surely, 22131212013432 is an apocalyptic number.

It is an amenable number.

2131212013432 is a deficient number, since it is larger than the sum of its proper divisors (1949832268328).

2131212013432 is a wasteful number, since it uses less digits than its factorization.

2131212013432 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5668117110 (or 5668117106 counting only the distinct ones).

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 2131212013432 its reverse (2343102121312), we get a palindrome (4474314134744).

The spelling of 2131212013432 in words is "two trillion, one hundred thirty-one billion, two hundred twelve million, thirteen thousand, four hundred thirty-two".

Divisors: 1 2 4 8 47 94 188 376 5668117057 11336234114 22672468228 45344936456 266401501679 532803003358 1065606006716 2131212013432