Base | Representation |
---|---|
bin | 110000011101010101010101… |
… | …000110101010010000011111 |
3 | 1000221121021010121122221020021 |
4 | 300131111111012222100133 |
5 | 210413242324000113002 |
6 | 2033134521205333011 |
7 | 62614361560111354 |
oct | 6035252506522037 |
9 | 1027537117587207 |
10 | 213122000004127 |
11 | 619a8594a17935 |
12 | 1baa057a707167 |
13 | 91bc41a5aa846 |
14 | 3a8b23484c62b |
15 | 1998bd4090737 |
hex | c1d5551aa41f |
213122000004127 has 2 divisors, whose sum is σ = 213122000004128. Its totient is φ = 213122000004126.
The previous prime is 213122000004073. The next prime is 213122000004203. The reversal of 213122000004127 is 721400000221312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213122000004127 - 219 = 213121999479839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213122000007127) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106561000002063 + 106561000002064.
It is an arithmetic number, because the mean of its divisors is an integer number (106561000002064).
Almost surely, 2213122000004127 is an apocalyptic number.
213122000004127 is a deficient number, since it is larger than the sum of its proper divisors (1).
213122000004127 is an equidigital number, since it uses as much as digits as its factorization.
213122000004127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1344, while the sum is 25.
Adding to 213122000004127 its reverse (721400000221312), we get a palindrome (934522000225439).
The spelling of 213122000004127 in words is "two hundred thirteen trillion, one hundred twenty-two billion, four thousand, one hundred twenty-seven".
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