Base | Representation |
---|---|
bin | 110000011101010101100111… |
… | …000011010000010001001100 |
3 | 1000221121021220121020020200012 |
4 | 300131111213003100101030 |
5 | 210413243433040214012 |
6 | 2033135011123052352 |
7 | 62614402204310243 |
oct | 6035254703202114 |
9 | 1027537817206605 |
10 | 213122301101132 |
11 | 619a8729980535 |
12 | 1baa06435110b8 |
13 | 91bc467aa0a57 |
14 | 3a8b26282995a |
15 | 1998c00719622 |
hex | c1d5670d044c |
213122301101132 has 24 divisors (see below), whose sum is σ = 373447461156672. Its totient is φ = 106423046755200.
The previous prime is 213122301101119. The next prime is 213122301101183. The reversal of 213122301101132 is 231101103221312.
It is a happy number.
It is a super-2 number, since 2×2131223011011322 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 213122301101098 and 213122301101107.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39642893 + ... + 44696795.
It is an arithmetic number, because the mean of its divisors is an integer number (15560310881528).
Almost surely, 2213122301101132 is an apocalyptic number.
It is an amenable number.
213122301101132 is a deficient number, since it is larger than the sum of its proper divisors (160325160055540).
213122301101132 is a wasteful number, since it uses less digits than its factorization.
213122301101132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5067569 (or 5067567 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 213122301101132 its reverse (231101103221312), we get a palindrome (444223404322444).
The spelling of 213122301101132 in words is "two hundred thirteen trillion, one hundred twenty-two billion, three hundred one million, one hundred one thousand, one hundred thirty-two".
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