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213124346036149 is a prime number
BaseRepresentation
bin110000011101010111100000…
…111100000011111110110101
31000221121111012010010201011011
4300131113200330003332311
5210413312130041124044
62033135550053112221
762614503655053022
oct6035274074037665
91027544163121134
10213124346036149
11619a9589219479
121baa0b14328671
1391bc70264bc82
143a8b3b8260549
151998cc0006134
hexc1d5e0f03fb5

213124346036149 has 2 divisors, whose sum is σ = 213124346036150. Its totient is φ = 213124346036148.

The previous prime is 213124346036083. The next prime is 213124346036179. The reversal of 213124346036149 is 941630643421312.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 204547003772049 + 8577342264100 = 14301993^2 + 2928710^2 .

It is a cyclic number.

It is not a de Polignac number, because 213124346036149 - 217 = 213124345905077 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (213124346036179) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106562173018074 + 106562173018075.

It is an arithmetic number, because the mean of its divisors is an integer number (106562173018075).

Almost surely, 2213124346036149 is an apocalyptic number.

It is an amenable number.

213124346036149 is a deficient number, since it is larger than the sum of its proper divisors (1).

213124346036149 is an equidigital number, since it uses as much as digits as its factorization.

213124346036149 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2239488, while the sum is 49.

The spelling of 213124346036149 in words is "two hundred thirteen trillion, one hundred twenty-four billion, three hundred forty-six million, thirty-six thousand, one hundred forty-nine".