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213131010101 = 1601831330547
BaseRepresentation
bin1100011001111110011…
…0010010000000110101
3202101010110121010000212
43012133212102000311
511442443014310401
6241524441115205
721253404460202
oct3063746220065
9671113533025
10213131010101
118242a998469
1235381188b05
13171378a1339
14a45bdd0ca9
155826153dbb
hex319f992035

213131010101 has 4 divisors (see below), whose sum is σ = 213132500832. Its totient is φ = 213129519372.

The previous prime is 213131010091. The next prime is 213131010119. The reversal of 213131010101 is 101010131312.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-213131010101 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213131010181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 505091 + ... + 825456.

It is an arithmetic number, because the mean of its divisors is an integer number (53283125208).

Almost surely, 2213131010101 is an apocalyptic number.

It is an amenable number.

213131010101 is a deficient number, since it is larger than the sum of its proper divisors (1490731).

213131010101 is a wasteful number, since it uses less digits than its factorization.

213131010101 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1490730.

The product of its (nonzero) digits is 18, while the sum is 14.

Adding to 213131010101 its reverse (101010131312), we get a palindrome (314141141413).

The spelling of 213131010101 in words is "two hundred thirteen billion, one hundred thirty-one million, ten thousand, one hundred one".

Divisors: 1 160183 1330547 213131010101