Base | Representation |
---|---|
bin | 1001101100010010110000… |
… | …11111001101110111100111 |
3 | 2210110111212102220212101211 |
4 | 10312021120133031313213 |
5 | 10243143223222113111 |
6 | 113155035243532251 |
7 | 4326551535305215 |
oct | 466113037156747 |
9 | 83414772825354 |
10 | 21313112301031 |
11 | 6877927298051 |
12 | 248275a22a087 |
13 | bb7a82b0c685 |
14 | 5397bb045cb5 |
15 | 26e609ee2521 |
hex | 1362587cdde7 |
21313112301031 has 2 divisors, whose sum is σ = 21313112301032. Its totient is φ = 21313112301030.
The previous prime is 21313112301011. The next prime is 21313112301109. The reversal of 21313112301031 is 13010321131312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-21313112301031 is a prime.
It is a super-2 number, since 2×213131123010312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 21313112300993 and 21313112301011.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21313112301011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10656556150515 + 10656556150516.
It is an arithmetic number, because the mean of its divisors is an integer number (10656556150516).
Almost surely, 221313112301031 is an apocalyptic number.
21313112301031 is a deficient number, since it is larger than the sum of its proper divisors (1).
21313112301031 is an equidigital number, since it uses as much as digits as its factorization.
21313112301031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 21313112301031 its reverse (13010321131312), we get a palindrome (34323433432343).
The spelling of 21313112301031 in words is "twenty-one trillion, three hundred thirteen billion, one hundred twelve million, three hundred one thousand, thirty-one".
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