Base | Representation |
---|---|
bin | 11111000001000001111… |
… | …110001100100000110011 |
3 | 21112202112200002002210201 |
4 | 133001001332030200303 |
5 | 234410112103231120 |
6 | 4311053450140031 |
7 | 306663225122551 |
oct | 37010176144063 |
9 | 7482480062721 |
10 | 2131410602035 |
11 | 751a207a0120 |
12 | 2a50b9121617 |
13 | 125cb675a260 |
14 | 7523742abd1 |
15 | 3a699acc40a |
hex | 1f041f8c833 |
2131410602035 has 32 divisors (see below), whose sum is σ = 3004974624960. Its totient is φ = 1430813798400.
The previous prime is 2131410602023. The next prime is 2131410602051. The reversal of 2131410602035 is 5302060141312.
It is not a de Polignac number, because 2131410602035 - 211 = 2131410599987 is a prime.
It is a super-2 number, since 2×21314106020352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2131410601994 and 2131410602012.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 20690055 + ... + 20792815.
It is an arithmetic number, because the mean of its divisors is an integer number (93905457030).
Almost surely, 22131410602035 is an apocalyptic number.
2131410602035 is a deficient number, since it is larger than the sum of its proper divisors (873564022925).
2131410602035 is a wasteful number, since it uses less digits than its factorization.
2131410602035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 131799.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 2131410602035 its reverse (5302060141312), we get a palindrome (7433470743347).
The spelling of 2131410602035 in words is "two trillion, one hundred thirty-one billion, four hundred ten million, six hundred two thousand, thirty-five".
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