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213141113 is a prime number
BaseRepresentation
bin11001011010001…
…00011001111001
3112212001200122022
430231010121321
5414031003423
633052204225
75165445443
oct1455043171
9485050568
10213141113
11aa349089
125b469675
1335208803
1420443493
1513aa2dc8
hexcb44679

213141113 has 2 divisors, whose sum is σ = 213141114. Its totient is φ = 213141112.

The previous prime is 213141091. The next prime is 213141157. The reversal of 213141113 is 311141312.

213141113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 165971689 + 47169424 = 12883^2 + 6868^2 .

It is a cyclic number.

It is not a de Polignac number, because 213141113 - 28 = 213140857 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 213141091 and 213141100.

It is not a weakly prime, because it can be changed into another prime (213140113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106570556 + 106570557.

It is an arithmetic number, because the mean of its divisors is an integer number (106570557).

Almost surely, 2213141113 is an apocalyptic number.

It is an amenable number.

213141113 is a deficient number, since it is larger than the sum of its proper divisors (1).

213141113 is an equidigital number, since it uses as much as digits as its factorization.

213141113 is an evil number, because the sum of its binary digits is even.

The product of its digits is 72, while the sum is 17.

The square root of 213141113 is about 14599.3531706031. The cubic root of 213141113 is about 597.3411170481.

Adding to 213141113 its reverse (311141312), we get a palindrome (524282425).

The spelling of 213141113 in words is "two hundred thirteen million, one hundred forty-one thousand, one hundred thirteen".