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21314142105643 is a prime number
BaseRepresentation
bin1001101100010100101011…
…10111100111000000101011
32210110121112012200100202101
410312022111313213000223
510243202330334340033
6113155325352114231
74326616211432062
oct466122567470053
983417465610671
1021314142105643
116878305618542
1224829a7095977
13bb7bb828390a
14539877b111d9
1526e66a60e97d
hex136295de702b

21314142105643 has 2 divisors, whose sum is σ = 21314142105644. Its totient is φ = 21314142105642.

The previous prime is 21314142105623. The next prime is 21314142105667. The reversal of 21314142105643 is 34650124141312.

It is a happy number.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 21314142105643 - 29 = 21314142105131 is a prime.

It is not a weakly prime, because it can be changed into another prime (21314142105623) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657071052821 + 10657071052822.

It is an arithmetic number, because the mean of its divisors is an integer number (10657071052822).

Almost surely, 221314142105643 is an apocalyptic number.

21314142105643 is a deficient number, since it is larger than the sum of its proper divisors (1).

21314142105643 is an equidigital number, since it uses as much as digits as its factorization.

21314142105643 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 37.

Adding to 21314142105643 its reverse (34650124141312), we get a palindrome (55964266246955).

The spelling of 21314142105643 in words is "twenty-one trillion, three hundred fourteen billion, one hundred forty-two million, one hundred five thousand, six hundred forty-three".