Base | Representation |
---|---|
bin | 1001101100010100101011… |
… | …10111100111000000101011 |
3 | 2210110121112012200100202101 |
4 | 10312022111313213000223 |
5 | 10243202330334340033 |
6 | 113155325352114231 |
7 | 4326616211432062 |
oct | 466122567470053 |
9 | 83417465610671 |
10 | 21314142105643 |
11 | 6878305618542 |
12 | 24829a7095977 |
13 | bb7bb828390a |
14 | 539877b111d9 |
15 | 26e66a60e97d |
hex | 136295de702b |
21314142105643 has 2 divisors, whose sum is σ = 21314142105644. Its totient is φ = 21314142105642.
The previous prime is 21314142105623. The next prime is 21314142105667. The reversal of 21314142105643 is 34650124141312.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 21314142105643 - 29 = 21314142105131 is a prime.
It is not a weakly prime, because it can be changed into another prime (21314142105623) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657071052821 + 10657071052822.
It is an arithmetic number, because the mean of its divisors is an integer number (10657071052822).
Almost surely, 221314142105643 is an apocalyptic number.
21314142105643 is a deficient number, since it is larger than the sum of its proper divisors (1).
21314142105643 is an equidigital number, since it uses as much as digits as its factorization.
21314142105643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 69120, while the sum is 37.
Adding to 21314142105643 its reverse (34650124141312), we get a palindrome (55964266246955).
The spelling of 21314142105643 in words is "twenty-one trillion, three hundred fourteen billion, one hundred forty-two million, one hundred five thousand, six hundred forty-three".
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