Base | Representation |
---|---|
bin | 10011110110011100… |
… | …000010000110001101 |
3 | 2001000102211100211112 |
4 | 103312130002012031 |
5 | 322122442203231 |
6 | 13443001501405 |
7 | 1353122343413 |
oct | 236634020615 |
9 | 61012740745 |
10 | 21314412941 |
11 | 9048480a08 |
12 | 416a1a1865 |
13 | 2018abac83 |
14 | 1062ab92b3 |
15 | 84b35692b |
hex | 4f670218d |
21314412941 has 2 divisors, whose sum is σ = 21314412942. Its totient is φ = 21314412940.
The previous prime is 21314412937. The next prime is 21314412943. The reversal of 21314412941 is 14921441312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 20262383716 + 1052029225 = 142346^2 + 32435^2 .
It is a cyclic number.
It is not a de Polignac number, because 21314412941 - 22 = 21314412937 is a prime.
Together with 21314412943, it forms a pair of twin primes.
It is a Chen prime.
It is a junction number, because it is equal to n+sod(n) for n = 21314412898 and 21314412907.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21314412943) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10657206470 + 10657206471.
It is an arithmetic number, because the mean of its divisors is an integer number (10657206471).
Almost surely, 221314412941 is an apocalyptic number.
It is an amenable number.
21314412941 is a deficient number, since it is larger than the sum of its proper divisors (1).
21314412941 is an equidigital number, since it uses as much as digits as its factorization.
21314412941 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6912, while the sum is 32.
The spelling of 21314412941 in words is "twenty-one billion, three hundred fourteen million, four hundred twelve thousand, nine hundred forty-one".
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