Base | Representation |
---|---|
bin | 11111000001000011110… |
… | …111010001011000111111 |
3 | 21112202121212210122002012 |
4 | 133001003313101120333 |
5 | 234410143214411224 |
6 | 4311100542321435 |
7 | 306664061654345 |
oct | 37010367213077 |
9 | 7482555718065 |
10 | 2131442341439 |
11 | 751a376a9434 |
12 | 2a510788927b |
13 | 125cc01c0b78 |
14 | 7523b72d995 |
15 | 3a69c79b80e |
hex | 1f043dd163f |
2131442341439 has 2 divisors, whose sum is σ = 2131442341440. Its totient is φ = 2131442341438.
The previous prime is 2131442341423. The next prime is 2131442341451. The reversal of 2131442341439 is 9341432441312.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2131442341439 - 24 = 2131442341423 is a prime.
It is a Sophie Germain prime.
It is a junction number, because it is equal to n+sod(n) for n = 2131442341396 and 2131442341405.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131442341459) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065721170719 + 1065721170720.
It is an arithmetic number, because the mean of its divisors is an integer number (1065721170720).
Almost surely, 22131442341439 is an apocalyptic number.
2131442341439 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131442341439 is an equidigital number, since it uses as much as digits as its factorization.
2131442341439 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 248832, while the sum is 41.
The spelling of 2131442341439 in words is "two trillion, one hundred thirty-one billion, four hundred forty-two million, three hundred forty-one thousand, four hundred thirty-nine".
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