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213220411403 = 1931104768971
BaseRepresentation
bin1100011010010011101…
…1010100100000001011
3202101100200211011120012
43012210323110200023
511443133411131103
6241541353222135
721255541410326
oct3064473244013
9671320734505
10213220411403
11824763aaa3a
12353a710194b
131715027390c
14a469c237bd
15582de132d8
hex31a4ed480b

213220411403 has 4 divisors (see below), whose sum is σ = 214325180568. Its totient is φ = 212115642240.

The previous prime is 213220411373. The next prime is 213220411421. The reversal of 213220411403 is 304114022312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213220411403 - 210 = 213220410379 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (213220411603) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 552384293 + ... + 552384678.

It is an arithmetic number, because the mean of its divisors is an integer number (53581295142).

Almost surely, 2213220411403 is an apocalyptic number.

213220411403 is a deficient number, since it is larger than the sum of its proper divisors (1104769165).

213220411403 is a wasteful number, since it uses less digits than its factorization.

213220411403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1104769164.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 213220411403 its reverse (304114022312), we get a palindrome (517334433715).

The spelling of 213220411403 in words is "two hundred thirteen billion, two hundred twenty million, four hundred eleven thousand, four hundred three".

Divisors: 1 193 1104768971 213220411403