Base | Representation |
---|---|
bin | 11111000001110111001… |
… | …010011011001000110111 |
3 | 21112211211212021121211121 |
4 | 133001313022123020313 |
5 | 234413424032000434 |
6 | 4311322205244411 |
7 | 310024312310335 |
oct | 37016712331067 |
9 | 7484755247747 |
10 | 2132303000119 |
11 | 7523394aaaa6 |
12 | 2a5307b63707 |
13 | 1260c95c1766 |
14 | 752bdb68b55 |
15 | 3a6ed1067b4 |
hex | 1f07729b237 |
2132303000119 has 2 divisors, whose sum is σ = 2132303000120. Its totient is φ = 2132303000118.
The previous prime is 2132303000099. The next prime is 2132303000153. The reversal of 2132303000119 is 9110003032312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2132303000119 - 225 = 2132269445687 is a prime.
It is a super-2 number, since 2×21323030001192 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 2132303000093 and 2132303000102.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2132303000159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1066151500059 + 1066151500060.
It is an arithmetic number, because the mean of its divisors is an integer number (1066151500060).
Almost surely, 22132303000119 is an apocalyptic number.
2132303000119 is a deficient number, since it is larger than the sum of its proper divisors (1).
2132303000119 is an equidigital number, since it uses as much as digits as its factorization.
2132303000119 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 972, while the sum is 25.
The spelling of 2132303000119 in words is "two trillion, one hundred thirty-two billion, three hundred three million, one hundred nineteen", and thus it is an aban number.
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