Base | Representation |
---|---|
bin | 11111000001111110111… |
… | …011101000011110010111 |
3 | 21112212011221112120222010 |
4 | 133001332323220132113 |
5 | 234414210413342221 |
6 | 4311343143035303 |
7 | 310030454216031 |
oct | 37017673503627 |
9 | 7485157476863 |
10 | 2132433340311 |
11 | 7523a603456a |
12 | 2a534373bb33 |
13 | 12611a5c9031 |
14 | 752d31b6c51 |
15 | 3a7097a0c76 |
hex | 1f07eee8797 |
2132433340311 has 32 divisors (see below), whose sum is σ = 2978759443968. Its totient is φ = 1354371258240.
The previous prime is 2132433340307. The next prime is 2132433340313. The reversal of 2132433340311 is 1130433342312.
It is not a de Polignac number, because 2132433340311 - 22 = 2132433340307 is a prime.
It is a super-4 number, since 4×21324333403114 (a number of 50 digits) contains 4444 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2132433340313) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17338245 + ... + 17460801.
It is an arithmetic number, because the mean of its divisors is an integer number (93086232624).
Almost surely, 22132433340311 is an apocalyptic number.
2132433340311 is a deficient number, since it is larger than the sum of its proper divisors (846326103657).
2132433340311 is a wasteful number, since it uses less digits than its factorization.
2132433340311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 123591.
The product of its (nonzero) digits is 15552, while the sum is 30.
Adding to 2132433340311 its reverse (1130433342312), we get a palindrome (3262866682623).
The spelling of 2132433340311 in words is "two trillion, one hundred thirty-two billion, four hundred thirty-three million, three hundred forty thousand, three hundred eleven".
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