Base | Representation |
---|---|
bin | 11111000010000100010… |
… | …011101011110001000111 |
3 | 21112212102020020202210102 |
4 | 133002010103223301013 |
5 | 234414402011000320 |
6 | 4311400124114315 |
7 | 310032630635441 |
oct | 37020423536107 |
9 | 7485366222712 |
10 | 2132523531335 |
11 | 752441a363aa |
12 | 2a536999599b |
13 | 1261331b6bc2 |
14 | 75301173491 |
15 | 3a712669175 |
hex | 1f0844ebc47 |
2132523531335 has 4 divisors (see below), whose sum is σ = 2559028237608. Its totient is φ = 1706018825064.
The previous prime is 2132523531323. The next prime is 2132523531379. The reversal of 2132523531335 is 5331353252312.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 2132523531335 - 24 = 2132523531319 is a prime.
It is a super-2 number, since 2×21325235313352 (a number of 25 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 213252353129 + ... + 213252353138.
It is an arithmetic number, because the mean of its divisors is an integer number (639757059402).
Almost surely, 22132523531335 is an apocalyptic number.
2132523531335 is a deficient number, since it is larger than the sum of its proper divisors (426504706273).
2132523531335 is an equidigital number, since it uses as much as digits as its factorization.
2132523531335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 426504706272.
The product of its digits is 243000, while the sum is 38.
Adding to 2132523531335 its reverse (5331353252312), we get a palindrome (7463876783647).
The spelling of 2132523531335 in words is "two trillion, one hundred thirty-two billion, five hundred twenty-three million, five hundred thirty-one thousand, three hundred thirty-five".
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