Base | Representation |
---|---|
bin | 1100011010101001000… |
… | …1011111110101111111 |
3 | 202101120221121101102022 |
4 | 3012222101133311333 |
5 | 11443324342023403 |
6 | 241554315550355 |
7 | 21261011012435 |
oct | 3065221376577 |
9 | 671527541368 |
10 | 213310111103 |
11 | 82511aa6721 |
12 | 3541115b3bb |
13 | 17165a1bc6b |
14 | a477ad2d55 |
15 | 5836c30d38 |
hex | 31aa45fd7f |
213310111103 has 2 divisors, whose sum is σ = 213310111104. Its totient is φ = 213310111102.
The previous prime is 213310111093. The next prime is 213310111121. The reversal of 213310111103 is 301111013312.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 213310111103 - 212 = 213310107007 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (213310111123) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 106655055551 + 106655055552.
It is an arithmetic number, because the mean of its divisors is an integer number (106655055552).
Almost surely, 2213310111103 is an apocalyptic number.
213310111103 is a deficient number, since it is larger than the sum of its proper divisors (1).
213310111103 is an equidigital number, since it uses as much as digits as its factorization.
213310111103 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 213310111103 its reverse (301111013312), we get a palindrome (514421124415).
The spelling of 213310111103 in words is "two hundred thirteen billion, three hundred ten million, one hundred eleven thousand, one hundred three".
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