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213311310103 = 613496906723
BaseRepresentation
bin1100011010101001011…
…0000100100100010111
3202101121000212022010201
43012222112010210113
511443330143410403
6241554401401331
721261024135163
oct3065226044427
9671530768121
10213311310103
1182512745531
1235411639247
131716604b928
14a477d25ca3
155836dbb21d
hex31aa584917

213311310103 has 4 divisors (see below), whose sum is σ = 216808216888. Its totient is φ = 209814403320.

The previous prime is 213311310089. The next prime is 213311310109. The reversal of 213311310103 is 301013113312.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 213311310103 - 213 = 213311301911 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213311310109) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1748453301 + ... + 1748453422.

It is an arithmetic number, because the mean of its divisors is an integer number (54202054222).

Almost surely, 2213311310103 is an apocalyptic number.

213311310103 is a deficient number, since it is larger than the sum of its proper divisors (3496906785).

213311310103 is an equidigital number, since it uses as much as digits as its factorization.

213311310103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3496906784.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 213311310103 its reverse (301013113312), we get a palindrome (514324423415).

The spelling of 213311310103 in words is "two hundred thirteen billion, three hundred eleven million, three hundred ten thousand, one hundred three".

Divisors: 1 61 3496906723 213311310103