213311335040401 has 8 divisors (see below), whose sum is σ = 229743707047400. Its totient is φ = 196882364143872.

The previous prime is 213311335040381. The next prime is 213311335040413. The reversal of 213311335040401 is 104040533113312.

It can be written as a sum of positive squares in 4 ways, for example, as 15321783633025 + 197989551407376 = 3914305^2 + 14070876^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 213311335040401 - 2¹⁵ = 213311335007633 is a prime.

It is a super-3 number, since 3×213311335040401³ (a number of 44 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (213311335040491) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 850147350 + ... + 850398223.

It is an arithmetic number, because the mean of its divisors is an integer number (28717963380925).

Almost surely, 2^{213311335040401} is an apocalyptic number.

It is an amenable number.

213311335040401 is a deficient number, since it is larger than the sum of its proper divisors (16432372006999).

213311335040401 is a wasteful number, since it uses less digits than its factorization.

213311335040401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1700555235.

The product of its (nonzero) digits is 12960, while the sum is 31.

Adding to 213311335040401 its reverse (104040533113312), we get a palindrome (317351868153713).

The spelling of 213311335040401 in words is "two hundred thirteen trillion, three hundred eleven billion, three hundred thirty-five million, forty thousand, four hundred one".