213322014411133 has 4 divisors (see below), whose sum is σ = 213322047420348. Its totient is φ = 213321981401920.

The previous prime is 213322014411131. The next prime is 213322014411137. The reversal of 213322014411133 is 331114410223312.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 42357942856804 + 170964071554329 = 6508298^2 + 13075323^2 .

It is a cyclic number.

It is not a de Polignac number, because 213322014411133 - 2¹ = 213322014411131 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 213322014411095 and 213322014411104.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (213322014411131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3277228 + ... + 20913733.

It is an arithmetic number, because the mean of its divisors is an integer number (53330511855087).

Almost surely, 2^{213322014411133} is an apocalyptic number.

It is an amenable number.

213322014411133 is a deficient number, since it is larger than the sum of its proper divisors (33009215).

213322014411133 is an equidigital number, since it uses as much as digits as its factorization.

213322014411133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 33009214.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 213322014411133 its reverse (331114410223312), we get a palindrome (544436424634445).

The spelling of 213322014411133 in words is "two hundred thirteen trillion, three hundred twenty-two billion, fourteen million, four hundred eleven thousand, one hundred thirty-three".