21333011121997 has 2 divisors, whose sum is σ = 21333011121998. Its totient is φ = 21333011121996.

The previous prime is 21333011121977. The next prime is 21333011122013. The reversal of 21333011121997 is 79912111033312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 16900411442121 + 4432599679876 = 4111011^2 + 2105374^2 .

It is a cyclic number.

It is not a de Polignac number, because 21333011121997 - 2³⁵ = 21298651383629 is a prime.

It is a super-3 number, since 3×21333011121997³ (a number of 41 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21333011121977) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10666505560998 + 10666505560999.

It is an arithmetic number, because the mean of its divisors is an integer number (10666505560999).

Almost surely, 2^{21333011121997} is an apocalyptic number.

It is an amenable number.

21333011121997 is a deficient number, since it is larger than the sum of its proper divisors (1).

21333011121997 is an equidigital number, since it uses as much as digits as its factorization.

21333011121997 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 61236, while the sum is 43.

The spelling of 21333011121997 in words is "twenty-one trillion, three hundred thirty-three billion, eleven million, one hundred twenty-one thousand, nine hundred ninety-seven".