Base | Representation |
---|---|
bin | 1001101100110111110101… |
… | …00011001100011101011101 |
3 | 2210112102020020001201010112 |
4 | 10312123322203030131131 |
5 | 10244010001321401023 |
6 | 113212130000415405 |
7 | 4331154621426443 |
oct | 466337243143535 |
9 | 83472206051115 |
10 | 21333011122013 |
11 | 688530869a848 |
12 | 2486592317565 |
13 | bb990454cc66 |
14 | 53a747b10b93 |
15 | 26edc1e24478 |
hex | 1366fa8cc75d |
21333011122013 has 2 divisors, whose sum is σ = 21333011122014. Its totient is φ = 21333011122012.
The previous prime is 21333011121997. The next prime is 21333011122019. The reversal of 21333011122013 is 31022111033312.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 13717519616089 + 7615491505924 = 3703717^2 + 2759618^2 .
It is a cyclic number.
It is not a de Polignac number, because 21333011122013 - 24 = 21333011121997 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 21333011122013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (21333011122019) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10666505561006 + 10666505561007.
It is an arithmetic number, because the mean of its divisors is an integer number (10666505561007).
Almost surely, 221333011122013 is an apocalyptic number.
It is an amenable number.
21333011122013 is a deficient number, since it is larger than the sum of its proper divisors (1).
21333011122013 is an equidigital number, since it uses as much as digits as its factorization.
21333011122013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 21333011122013 its reverse (31022111033312), we get a palindrome (52355122155325).
The spelling of 21333011122013 in words is "twenty-one trillion, three hundred thirty-three billion, eleven million, one hundred twenty-two thousand, thirteen".
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