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21333011122013 is a prime number
BaseRepresentation
bin1001101100110111110101…
…00011001100011101011101
32210112102020020001201010112
410312123322203030131131
510244010001321401023
6113212130000415405
74331154621426443
oct466337243143535
983472206051115
1021333011122013
11688530869a848
122486592317565
13bb990454cc66
1453a747b10b93
1526edc1e24478
hex1366fa8cc75d

21333011122013 has 2 divisors, whose sum is σ = 21333011122014. Its totient is φ = 21333011122012.

The previous prime is 21333011121997. The next prime is 21333011122019. The reversal of 21333011122013 is 31022111033312.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 13717519616089 + 7615491505924 = 3703717^2 + 2759618^2 .

It is a cyclic number.

It is not a de Polignac number, because 21333011122013 - 24 = 21333011121997 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 21333011122013.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (21333011122019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 10666505561006 + 10666505561007.

It is an arithmetic number, because the mean of its divisors is an integer number (10666505561007).

Almost surely, 221333011122013 is an apocalyptic number.

It is an amenable number.

21333011122013 is a deficient number, since it is larger than the sum of its proper divisors (1).

21333011122013 is an equidigital number, since it uses as much as digits as its factorization.

21333011122013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 21333011122013 its reverse (31022111033312), we get a palindrome (52355122155325).

The spelling of 21333011122013 in words is "twenty-one trillion, three hundred thirty-three billion, eleven million, one hundred twenty-two thousand, thirteen".