Base | Representation |
---|---|
bin | 11111000010111111111… |
… | …000110111000000011101 |
3 | 21112221222220011202201202 |
4 | 133002333320313000131 |
5 | 234423423410214240 |
6 | 4312043233045245 |
7 | 310066456255415 |
oct | 37027770670035 |
9 | 7487886152652 |
10 | 2133523132445 |
11 | 752905207521 |
12 | 2a55a86b6825 |
13 | 126262314653 |
14 | 75397c19645 |
15 | 3a7702bc315 |
hex | 1f0bfe3701d |
2133523132445 has 8 divisors (see below), whose sum is σ = 2560594018560. Its totient is φ = 1706574332880.
The previous prime is 2133523132417. The next prime is 2133523132451. The reversal of 2133523132445 is 5442313253312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 2133523132445 - 238 = 1858645225501 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2133523132399 and 2133523132408.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 30483185 + ... + 30553094.
It is an arithmetic number, because the mean of its divisors is an integer number (320074252320).
Almost surely, 22133523132445 is an apocalyptic number.
It is an amenable number.
2133523132445 is a deficient number, since it is larger than the sum of its proper divisors (427070886115).
2133523132445 is an equidigital number, since it uses as much as digits as its factorization.
2133523132445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 61043275.
The product of its digits is 259200, while the sum is 38.
Adding to 2133523132445 its reverse (5442313253312), we get a palindrome (7575836385757).
The spelling of 2133523132445 in words is "two trillion, one hundred thirty-three billion, five hundred twenty-three million, one hundred thirty-two thousand, four hundred forty-five".
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