Base | Representation |
---|---|
bin | 1001101101000101101010… |
… | …11010011011100110011111 |
3 | 2210120010102000221021221020 |
4 | 10312202311122123212133 |
5 | 10244120210412201143 |
6 | 113215355135335223 |
7 | 4331540011445451 |
oct | 466426532334637 |
9 | 83503360837836 |
10 | 21340441131423 |
11 | 6888480746897 |
12 | 2487b06681513 |
13 | bba51997382b |
14 | 53ac508042d1 |
15 | 2701a937d883 |
hex | 1368b569b99f |
21340441131423 has 4 divisors (see below), whose sum is σ = 28453921508568. Its totient is φ = 14226960754280.
The previous prime is 21340441131349. The next prime is 21340441131461. The reversal of 21340441131423 is 32413114404312.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 21340441131423 - 214 = 21340441115039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (21340441131323) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3556740188568 + ... + 3556740188573.
It is an arithmetic number, because the mean of its divisors is an integer number (7113480377142).
Almost surely, 221340441131423 is an apocalyptic number.
21340441131423 is a deficient number, since it is larger than the sum of its proper divisors (7113480377145).
21340441131423 is an equidigital number, since it uses as much as digits as its factorization.
21340441131423 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 7113480377144.
The product of its (nonzero) digits is 27648, while the sum is 33.
Adding to 21340441131423 its reverse (32413114404312), we get a palindrome (53753555535735).
The spelling of 21340441131423 in words is "twenty-one trillion, three hundred forty billion, four hundred forty-one million, one hundred thirty-one thousand, four hundred twenty-three".
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