Base | Representation |
---|---|
bin | 10011111000000010… |
… | …010110000100011001 |
3 | 2001002022021222122002 |
4 | 103320002112010121 |
5 | 322201323432213 |
6 | 13445400410345 |
7 | 1353566330312 |
oct | 237002260431 |
9 | 61068258562 |
10 | 21341233433 |
11 | 906162a603 |
12 | 41771769b5 |
13 | 202151b9a0 |
14 | 106649b609 |
15 | 84d8a3658 |
hex | 4f8096119 |
21341233433 has 4 divisors (see below), whose sum is σ = 22982866788. Its totient is φ = 19699600080.
The previous prime is 21341233391. The next prime is 21341233457. The reversal of 21341233433 is 33433214312.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 13861059289 + 7480174144 = 117733^2 + 86488^2 .
It is a cyclic number.
It is not a de Polignac number, because 21341233433 - 26 = 21341233369 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 21341233396 and 21341233405.
It is not an unprimeable number, because it can be changed into a prime (21341239433) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 820816658 + ... + 820816683.
It is an arithmetic number, because the mean of its divisors is an integer number (5745716697).
Almost surely, 221341233433 is an apocalyptic number.
It is an amenable number.
21341233433 is a deficient number, since it is larger than the sum of its proper divisors (1641633355).
21341233433 is a wasteful number, since it uses less digits than its factorization.
21341233433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1641633354.
The product of its digits is 15552, while the sum is 29.
Adding to 21341233433 its reverse (33433214312), we get a palindrome (54774447745).
The spelling of 21341233433 in words is "twenty-one billion, three hundred forty-one million, two hundred thirty-three thousand, four hundred thirty-three".
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