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21341300451 = 37113766817
BaseRepresentation
bin10011111000000010…
…100110011011100011
32001002022102101120020
4103320002212123203
5322201333103301
613445402044523
71353600026562
oct237002463343
961068371506
1021341300451
119061675999
1241771a9743
132021543343
1410664b7bd9
1584d8b8436
hex4f80a66e3

21341300451 has 4 divisors (see below), whose sum is σ = 28455067272. Its totient is φ = 14227533632.

The previous prime is 21341300447. The next prime is 21341300483. The reversal of 21341300451 is 15400314312.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 21341300451 - 22 = 21341300447 is a prime.

It is a super-2 number, since 2×213413004512 (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (21341300401) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3556883406 + ... + 3556883411.

It is an arithmetic number, because the mean of its divisors is an integer number (7113766818).

Almost surely, 221341300451 is an apocalyptic number.

21341300451 is a deficient number, since it is larger than the sum of its proper divisors (7113766821).

21341300451 is an equidigital number, since it uses as much as digits as its factorization.

21341300451 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7113766820.

The product of its (nonzero) digits is 1440, while the sum is 24.

Adding to 21341300451 its reverse (15400314312), we get a palindrome (36741614763).

The spelling of 21341300451 in words is "twenty-one billion, three hundred forty-one million, three hundred thousand, four hundred fifty-one".

Divisors: 1 3 7113766817 21341300451