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21342000113 = 76434741613
BaseRepresentation
bin10011111000000101…
…010001001111110001
32001002100201221022122
4103320011101033301
5322202023000423
613445425044025
71353606002450
oct237005211761
961070657278
1021342000113
119062003625
124177486615
132021729945
14106661ab97
1584d9a58c8
hex4f81513f1

21342000113 has 8 divisors (see below), whose sum is σ = 24428795328. Its totient is φ = 18264689424.

The previous prime is 21342000109. The next prime is 21342000133. The reversal of 21342000113 is 31100024312.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 21342000113 - 22 = 21342000109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 21342000091 and 21342000100.

It is not an unprimeable number, because it can be changed into a prime (21342000133) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2366306 + ... + 2375307.

It is an arithmetic number, because the mean of its divisors is an integer number (3053599416).

Almost surely, 221342000113 is an apocalyptic number.

It is an amenable number.

21342000113 is a deficient number, since it is larger than the sum of its proper divisors (3086795215).

21342000113 is an equidigital number, since it uses as much as digits as its factorization.

21342000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4742263.

The product of its (nonzero) digits is 144, while the sum is 17.

Adding to 21342000113 its reverse (31100024312), we get a palindrome (52442024425).

The spelling of 21342000113 in words is "twenty-one billion, three hundred forty-two million, one hundred thirteen", and thus it is an aban number.

Divisors: 1 7 643 4501 4741613 33191291 3048857159 21342000113