Base | Representation |
---|---|
bin | 1100011011000011100… |
… | …1011011101111000111 |
3 | 202101212200201111011220 |
4 | 3012300321123233013 |
5 | 11444041314241320 |
6 | 242013325531423 |
7 | 21263530431216 |
oct | 3066071335707 |
9 | 671780644156 |
10 | 213421243335 |
11 | 82569800a43 |
12 | 35442413b73 |
13 | 17182a5c791 |
14 | a48878107d |
15 | 5841883e40 |
hex | 31b0e5bbc7 |
213421243335 has 8 divisors (see below), whose sum is σ = 341473989360. Its totient is φ = 113824663104.
The previous prime is 213421243319. The next prime is 213421243349. The reversal of 213421243335 is 533342124312.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 213421243335 - 24 = 213421243319 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 213421243296 and 213421243305.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7114041430 + ... + 7114041459.
It is an arithmetic number, because the mean of its divisors is an integer number (42684248670).
Almost surely, 2213421243335 is an apocalyptic number.
213421243335 is a deficient number, since it is larger than the sum of its proper divisors (128052746025).
213421243335 is a wasteful number, since it uses less digits than its factorization.
213421243335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14228082897.
The product of its digits is 51840, while the sum is 33.
Adding to 213421243335 its reverse (533342124312), we get a palindrome (746763367647).
The spelling of 213421243335 in words is "two hundred thirteen billion, four hundred twenty-one million, two hundred forty-three thousand, three hundred thirty-five".
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