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21342310413 = 37114103471
BaseRepresentation
bin10011111000000110…
…011101000000001101
32001002101022200222020
4103320012131000031
5322202112413123
613445435440353
71353611434224
oct237006350015
961071280866
1021342310413
1190621a5776
1241775b60b9
132021807c58
14106669bcbb
1584da177e3
hex4f819d00d

21342310413 has 4 divisors (see below), whose sum is σ = 28456413888. Its totient is φ = 14228206940.

The previous prime is 21342310411. The next prime is 21342310421. The reversal of 21342310413 is 31401324312.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 21342310413 - 21 = 21342310411 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (21342310411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3557051733 + ... + 3557051738.

It is an arithmetic number, because the mean of its divisors is an integer number (7114103472).

Almost surely, 221342310413 is an apocalyptic number.

It is an amenable number.

21342310413 is a deficient number, since it is larger than the sum of its proper divisors (7114103475).

21342310413 is an equidigital number, since it uses as much as digits as its factorization.

21342310413 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7114103474.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 21342310413 its reverse (31401324312), we get a palindrome (52743634725).

The spelling of 21342310413 in words is "twenty-one billion, three hundred forty-two million, three hundred ten thousand, four hundred thirteen".

Divisors: 1 3 7114103471 21342310413