Base | Representation |
---|---|
bin | 11111000011110110110… |
… | …010001100011111010111 |
3 | 21120001101002012102000220 |
4 | 133003312302030133113 |
5 | 234432320144213221 |
6 | 4312314453205423 |
7 | 310131341526261 |
oct | 37036662143727 |
9 | 7501332172026 |
10 | 2134444132311 |
11 | 753238082337 |
12 | 2a5805030873 |
13 | 12637b08159a |
14 | 75444280b31 |
15 | 3a7c60960c6 |
hex | 1f0f6c8c7d7 |
2134444132311 has 4 divisors (see below), whose sum is σ = 2845925509752. Its totient is φ = 1422962754872.
The previous prime is 2134444132277. The next prime is 2134444132319. The reversal of 2134444132311 is 1132314444312.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2134444132311 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2134444132319) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 355740688716 + ... + 355740688721.
It is an arithmetic number, because the mean of its divisors is an integer number (711481377438).
Almost surely, 22134444132311 is an apocalyptic number.
2134444132311 is a deficient number, since it is larger than the sum of its proper divisors (711481377441).
2134444132311 is an equidigital number, since it uses as much as digits as its factorization.
2134444132311 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 711481377440.
The product of its digits is 27648, while the sum is 33.
Adding to 2134444132311 its reverse (1132314444312), we get a palindrome (3266758576623).
The spelling of 2134444132311 in words is "two trillion, one hundred thirty-four billion, four hundred forty-four million, one hundred thirty-two thousand, three hundred eleven".
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