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2135314001203 = 3168881096813
BaseRepresentation
bin11111000100101010101…
…000011110110100110011
321120010121201000022211021
4133010222220132310303
5234441110341014303
64312541045400311
7310162033352215
oct37045250366463
97503551008737
102135314001203
117536440a4749
122a5a08409097
131264893583c6
14754c79d65b5
153a82761eebd
hex1f12aa1ed33

2135314001203 has 4 divisors (see below), whose sum is σ = 2204195098048. Its totient is φ = 2066432904360.

The previous prime is 2135314001173. The next prime is 2135314001213. The reversal of 2135314001203 is 3021004135312.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2135314001203 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2135314001213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34440548376 + ... + 34440548437.

It is an arithmetic number, because the mean of its divisors is an integer number (551048774512).

Almost surely, 22135314001203 is an apocalyptic number.

2135314001203 is a deficient number, since it is larger than the sum of its proper divisors (68881096845).

2135314001203 is an equidigital number, since it uses as much as digits as its factorization.

2135314001203 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 68881096844.

The product of its (nonzero) digits is 2160, while the sum is 25.

Adding to 2135314001203 its reverse (3021004135312), we get a palindrome (5156318136515).

The spelling of 2135314001203 in words is "two trillion, one hundred thirty-five billion, three hundred fourteen million, one thousand, two hundred three".

Divisors: 1 31 68881096813 2135314001203